What is the domain of f(x)=(sqrt(x+1))/x ?

The domain of f(x)=(sqrt(x+1))/x is -1 0

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domain of f(x)=(sqrt(x+1))/x

domain

f (x) = \frac{x + 1}{x}

- 1 \leq x < 0 or x > 0

Interval Notation

[- 1, 0) \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 1 \leq x < 0 or x > 0

f (x) = \frac{x}{x ^{2} - 25}

f (x) = x^{2} + 49

x

f (x) = \frac{e ^{x} + e ^{- x}}{3}

y = - 3 x + 6

What is the domain of f(x)=(sqrt(x+1))/x ?
The domain of f(x)=(sqrt(x+1))/x is -1<= x<0\lor x>0