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Popular >

midpoint (7,-6),(-5,8)

Solution

midpoint

(7, - 6), (- 5, 8)

Solution

(1, 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (7, - 6), (x_{2}, y_{2}) = (- 5, 8)

= (\frac{- 5 + 7}{2}, \frac{8 - 6}{2})

Refine

= (1, 1)

Popular Examples

extreme f(x)=x^2(7-x)^3 extreme points

f (x) = x^{2} (7 - x)^{3}

parity sec^2(θ)dθ parity

sec^{2} (θ) d θ

range of f(x)=3*e^{2x}range

f (x) = 3 \cdot e^{2 x}

inverse of f(x)=(2x-3)/(x+1)inverse

f (x) = \frac{2 x - 3}{x + 1}

extreme f(x)=x^3-4x^2-x+4 extreme points

f (x) = x^{3} - 4 x^{2} - x + 4

Frequently Asked Questions (FAQ)

What is the midpoint (7,-6),(-5,8) ?
The midpoint (7,-6),(-5,8) is (1,1)