What is the inverse of f(x)=(3x-4)/(2x+1) ?

The inverse of f(x)=(3x-4)/(2x+1) is (-4-x)/(2x-3)

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inverse of f(x)=(3x-4)/(2x+1)

inverse

f (x) = \frac{3 x - 4}{2 x + 1}

\frac{- 4 - x}{2 x - 3}

Solution steps

y = \frac{3 x - 4}{2 x + 1}

Replace

x

with

y

x = \frac{3 y - 4}{2 y + 1}

Solve for

y, x = \frac{3 y - 4}{2 y + 1}

\frac{- 4 - x}{2 x - 3}

f (x) = - x^{3} + 3 x^{2} - 2

f (x) = x^{3} - 9 x^{2} + 15 x - 6

(x^{2} - 7)^{3}

f (x) = \frac{5}{4 x - 8}

\frac{x ^{2} - 16}{3 x ^{2}}

What is the inverse of f(x)=(3x-4)/(2x+1) ?
The inverse of f(x)=(3x-4)/(2x+1) is (-4-x)/(2x-3)