What is the inflection f(x)=x^3+2x^2+x-7 ?

The inflection f(x)=x^3+2x^2+x-7 is (-2/3 ,-191/27)

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inflection f(x)=x^3+2x^2+x-7

inflection points

f (x) = x^{3} + 2 x^{2} + x - 7

(- \frac{2}{3}, - \frac{191}{27})

Solution steps

f^{''} (x) = 6 x + 4

Find intervals:

Concave Downward

: - \infty < x < - \frac{2}{3},

Concave Upward

: - \frac{2}{3} < x < \infty

Plug

x = - \frac{2}{3}

into

x^{3} + 2 x^{2} + x - 7 : - \frac{191}{27}

(- \frac{2}{3}, - \frac{191}{27})

5 x^{2} - 5 x

f (x) = 6 x - 5

f (x) = \frac{x ^{3}}{3} - 3 x^{2} - 7 x

\frac{5}{x} + 4

y = \frac{1}{4} x + 2

What is the inflection f(x)=x^3+2x^2+x-7 ?
The inflection f(x)=x^3+2x^2+x-7 is (-2/3 ,-191/27)