What is the critical y=x^2-7x^6 ?

The critical y=x^2-7x^6 is x=-1/(\sqrt[4]{21)},x=0,x= 1/(\sqrt[4]{21)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical y=x^2-7x^6

critical points

y = x^{2} - 7 x^{6}

Solution steps

x^{2} - 7 x^{6}

Find where

f^{'} (x)

is equal to zero or undefined

Identify critical points not in

f (x)

domain

Domain of

x^{2} - 7 x^{6} : - \infty < x < \infty

All critical points are in domain

\frac{7 x}{5 x - 6}

\frac{1}{3} lo g_{10} (2 x)

x^{2} + 2 x - 15

y = - e^{x + 1}

f (x) = \frac{- 5 - x}{5 - x}

What is the critical y=x^2-7x^6 ?
The critical y=x^2-7x^6 is x=-1/(\sqrt[4]{21)},x=0,x= 1/(\sqrt[4]{21)}