What is the domain of f(x)=sqrt((x^2-16)/(x^2+169)) ?

The domain of f(x)=sqrt((x^2-16)/(x^2+169)) is x = 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt((x^2-16)/(x^2+169))

domain

f (x) = \frac{x ^{2} - 16}{x ^{2} + 169}

x \leq - 4 or x \geq 4

Interval Notation

(- \infty, - 4] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 4

The function domain

x \leq - 4 or x \geq 4

\frac{x - 1}{2 - 3 x}

sin^{2} (θ)

f (x) = 2 x^{2} - 7

f (x) = 36 - x^{2} + x + 2

- 2 x + y = - 4

What is the domain of f(x)=sqrt((x^2-16)/(x^2+169)) ?
The domain of f(x)=sqrt((x^2-16)/(x^2+169)) is x<=-4\lor x>= 4