What is the extreme f(x)=2x^3-6x^2-18x+5 ?

The extreme f(x)=2x^3-6x^2-18x+5 is Maximum(-1,15),Minimum(3,-49)

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extreme f(x)=2x^3-6x^2-18x+5

extreme points

f (x) = 2 x^{3} - 6 x^{2} - 18 x + 5

Maximum (- 1, 15), Minimum (3, - 49)

Solution steps

f^{'} (x) = 6 x^{2} - 12 x - 18

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 1

into

2 x^{3} - 6 x^{2} - 18 x + 5 : 15

Maximum (- 1, 15)

Plug

x = 3

into

2 x^{3} - 6 x^{2} - 18 x + 5 : - 49

Minimum (3, - 49)

Maximum (- 1, 15), Minimum (3, - 49)

f (x) = x - 2 + 7

4 - x^{2}

f (x) = x^{\frac{1}{3}} (x + 4)

\frac{x - 4}{x ^{2} - 4 x}

f (x) = 6 (x - 5)^{\frac{2}{3}}

What is the extreme f(x)=2x^3-6x^2-18x+5 ?
The extreme f(x)=2x^3-6x^2-18x+5 is Maximum(-1,15),Minimum(3,-49)