What is the domain of x/(sqrt(x^2+7)) ?

The domain of x/(sqrt(x^2+7)) is -infinity <x<infinity

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domain of x/(sqrt(x^2+7))

domain

\frac{x}{x ^{2} + 7}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = x^{2} - 2 x + 1

(- 1, 8), (3, 5.5)

\frac{1}{x} + 8

g (x) = x^{2} - 4

What is the domain of x/(sqrt(x^2+7)) ?
The domain of x/(sqrt(x^2+7)) is -infinity <x<infinity