What is the asymptotes of f(x)=(x^3-5x^2+4)/(x^2-1) ?

The asymptotes of f(x)=(x^3-5x^2+4)/(x^2-1) is Vertical: x=-1,Slant: y=x-5

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asymptotes of f(x)=(x^3-5x^2+4)/(x^2-1)

asymptotes

f (x) = \frac{x ^{3} - 5 x ^{2} + 4}{x ^{2} - 1}

Vertical : x = - 1, Slant : y = x - 5

Solution steps

Vertical asymptotes of

\frac{x ^{3} - 5 x ^{2} + 4}{x ^{2} - 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{3} - 5 x ^{2} + 4}{x ^{2} - 1} :

None

Slant Asymptotes of

\frac{x ^{3} - 5 x ^{2} + 4}{x ^{2} - 1} : y = x - 5

Vertical : x = - 1, Slant : y = x - 5

f (x) = 2 x^{3} - 9 x^{2} - 24 x + 9

\frac{x}{x ^{2} - 1}

\frac{1}{x ^{3} + 1}

x - 1

- x^{2} + x + 30

What is the asymptotes of f(x)=(x^3-5x^2+4)/(x^2-1) ?
The asymptotes of f(x)=(x^3-5x^2+4)/(x^2-1) is Vertical: x=-1,Slant: y=x-5