What is the inflection f(x)=2x^3-3x^2+7x-8 ?

The inflection f(x)=2x^3-3x^2+7x-8 is (1/2 ,-5)

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inflection f(x)=2x^3-3x^2+7x-8

inflection points

f (x) = 2 x^{3} - 3 x^{2} + 7 x - 8

(\frac{1}{2}, - 5)

Solution steps

f^{''} (x) = 12 x - 6

Find intervals:

Concave Downward

: - \infty < x < \frac{1}{2},

Concave Upward

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

2 x^{3} - 3 x^{2} + 7 x - 8 : - 5

(\frac{1}{2}, - 5)

f (x) = ln (2 + ln (x))

(0, 1), (- 5, - 6)

y = 6 x^{3}

f (x) = \frac{2100}{x} + 4 x

What is the inflection f(x)=2x^3-3x^2+7x-8 ?
The inflection f(x)=2x^3-3x^2+7x-8 is (1/2 ,-5)