What is the extreme f(x)=(2100)/x+4x ?

The extreme f(x)=(2100)/x+4x is Maximum(-5sqrt(21),-40sqrt(21)),Minimum(5sqrt(21),40sqrt(21))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=(2100)/x+4x

extreme points

f (x) = \frac{2100}{x} + 4 x

Maximum (- 521, - 4021), Minimum (521, 4021)

Solution steps

f^{'} (x) = - \frac{2100}{x ^{2}} + 4

Find intervals:

Increasing

: - \infty < x < - 521,

Decreasing

: - 521 < x < 0,

Decreasing

: 0 < x < 521,

Increasing

: 521 < x < \infty

Plug

x = - 521

into

\frac{2100}{x} + 4 x : - 4021

Maximum (- 521, - 4021)

Plug

x = 521

into

\frac{2100}{x} + 4 x : 4021

Minimum (521, 4021)

Maximum (- 521, - 4021), Minimum (521, 4021)

f (x) = \frac{2 x ^{2} - 3}{x ^{2} - 5 x + 6}

f (x) = 3 x^{2} + 2

(5, 10.388), (7, 13.312)

(6, - 9), (5, - 4)

f (x) = \frac{2 x + 1}{x - 1}

What is the extreme f(x)=(2100)/x+4x ?
The extreme f(x)=(2100)/x+4x is Maximum(-5sqrt(21),-40sqrt(21)),Minimum(5sqrt(21),40sqrt(21))