What is the domain of 9/(sqrt(x+2)) ?

The domain of 9/(sqrt(x+2)) is x>-2

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domain of 9/(sqrt(x+2))

domain

\frac{9}{x + 2}

x > - 2

Interval Notation

(- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = - 2

Combine real regions and undefined points for final function domain

x > - 2

f (x) = \frac{x}{x ^{2} + 1}

y = \frac{3}{2} x + 2

f (x) = - 0.1 t^{2} + 0.8 t + 98.8

f (x) = \frac{x ^{2} - 6 x + 5}{x - 5}

\frac{2 x + 1}{x - 1}