What is the critical x^3-2x^2+x+8 ?

The critical x^3-2x^2+x+8 is x= 1/3 ,x=1

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critical x^3-2x^2+x+8

critical points

x^{3} - 2 x^{2} + x + 8

x = \frac{1}{3}, x = 1

Solution steps

x^{3} - 2 x^{2} + x + 8

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{3}, x = 1

Identify critical points not in

f (x)

domain

Domain of

x^{3} - 2 x^{2} + x + 8 : - \infty < x < \infty

All critical points are in domain

x = \frac{1}{3}, x = 1

y = x - 2

f (x) = x^{3} - 6 x^{2} - 96 x

f (x) = x + 4 - 2

f (x) = \frac{1}{x + 2}

y = - (X - 3)^{2} + 1