What is the domain of f(x)= 3/(sqrt(2x-4)) ?

The domain of f(x)= 3/(sqrt(2x-4)) is x>2

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domain of f(x)= 3/(sqrt(2x-4))

domain

f (x) = \frac{3}{2 x - 4}

x > 2

Interval Notation

(2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x > 2

f (x) = x^{6}

(3 - 2) (- 4 - 5)

y = 3 cos (2 x)

f (x) = 5 x - 6

f (x) = 3 x^{3} - 7

What is the domain of f(x)= 3/(sqrt(2x-4)) ?
The domain of f(x)= 3/(sqrt(2x-4)) is x>2