en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

midpoint (-2,4),(3,-3)

Solution

midpoint

(- 2, 4), (3, - 3)

Solution

(\frac{1}{2}, \frac{1}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 2, 4), (x_{2}, y_{2}) = (3, - 3)

= (\frac{3 - 2}{2}, \frac{- 3 + 4}{2})

Refine

= (\frac{1}{2}, \frac{1}{2})

Popular Examples

parallel 2x-5y=15,(1/2 ,-3/4)parallel

2 x - 5 y = 15, (\frac{1}{2}, - \frac{3}{4})

domain of (-7(4+x))/((2^x-8)(-1-3x)^2)domain

\frac{- 7 ( 4 + x )}{( 2 ^{x} - 8 ) ( - 1 - 3 x ) ^{2}}

perpendicular y=20-3x perpendicular

y = 20 - 3 x

critical ln(7-6x^2)critical points

ln (7 - 6 x^{2})

inverse of (x+1)/(x-4)inverse

\frac{x + 1}{x - 4}

Frequently Asked Questions (FAQ)

What is the midpoint (-2,4),(3,-3) ?
The midpoint (-2,4),(3,-3) is (1/2 , 1/2)