What is the domain of f(x)=sqrt(8-x^2) ?

The domain of f(x)=sqrt(8-x^2) is -2sqrt(2)<= x<= 2sqrt(2)

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domain of f(x)=sqrt(8-x^2)

domain

f (x) = 8 - x^{2}

- 22 \leq x \leq 22

Interval Notation

[- 22, 22]

Solution steps

Find non-negative values for radicals:

- 22 \leq x \leq 22

The function domain

- 22 \leq x \leq 22

f (x) = \frac{7 x - 2}{x + 9}

f (x) = ∣ x ∣ - 3

4 x - x^{2} + 12

f (x) = \frac{x ^{2} + x}{x ^{2} - 7}

f (x) = 2 x^{2} - 1

What is the domain of f(x)=sqrt(8-x^2) ?
The domain of f(x)=sqrt(8-x^2) is -2sqrt(2)<= x<= 2sqrt(2)