What is the domain of f(x)=(2x-6)/(x^2+4x-5) ?

The domain of f(x)=(2x-6)/(x^2+4x-5) is x 1

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domain of f(x)=(2x-6)/(x^2+4x-5)

domain

f (x) = \frac{2 x - 6}{x ^{2} + 4 x - 5}

x < - 5 or - 5 < x < 1 or x > 1

Interval Notation

(- \infty, - 5) \cup (- 5, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 5

The function domain

x < - 5 or - 5 < x < 1 or x > 1

f (x) = \frac{x + 8}{x ^{2} - 9}

y - 5 = 3 x^{2} - 6

(- 6, - 3), (8, 5)

f (x) = lo g_{x} (x - 4)

What is the domain of f(x)=(2x-6)/(x^2+4x-5) ?
The domain of f(x)=(2x-6)/(x^2+4x-5) is x<-5\lor-5<x<1\lor x>1