What is the domain of f(x)=(x+8)/(x^2-9) ?

The domain of f(x)=(x+8)/(x^2-9) is x 3

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domain of f(x)=(x+8)/(x^2-9)

domain

f (x) = \frac{x + 8}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

y - 5 = 3 x^{2} - 6

(- 6, - 3), (8, 5)

f (x) = lo g_{x} (x - 4)

2 x + y = - 6

What is the domain of f(x)=(x+8)/(x^2-9) ?
The domain of f(x)=(x+8)/(x^2-9) is x<-3\lor-3<x<3\lor x>3