What is the domain of sqrt(x^2-5x) ?

The domain of sqrt(x^2-5x) is x = 5

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domain of sqrt(x^2-5x)

domain

x^{2} - 5 x

x \leq 0 or x \geq 5

Interval Notation

(- \infty, 0] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 5

The function domain

x \leq 0 or x \geq 5

f (x) = x^{3} + 6

f (x) = x + 4 + 6

- \frac{1}{2} 2^{x + 5} + 8

f (x) = \frac{2 x ^{2} - 8}{x - 1}

f (x) = x^{3} - 2 x^{2} + x

What is the domain of sqrt(x^2-5x) ?
The domain of sqrt(x^2-5x) is x<= 0\lor x>= 5