What is the asymptotes of f(x)=(2x^2-8)/(x-1) ?

The asymptotes of f(x)=(2x^2-8)/(x-1) is Vertical: x=1,Slant: y=2x+2

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asymptotes of f(x)=(2x^2-8)/(x-1)

asymptotes

f (x) = \frac{2 x ^{2} - 8}{x - 1}

Vertical : x = 1, Slant : y = 2 x + 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} - 8}{x - 1} : x = 1

Horizontal Asymptotes of

\frac{2 x ^{2} - 8}{x - 1} :

None

Slant Asymptotes of

\frac{2 x ^{2} - 8}{x - 1} : y = 2 x + 2

Vertical : x = 1, Slant : y = 2 x + 2

f (x) = x^{3} - 2 x^{2} + x

y = x^{2} - x

f (x) = e^{x^{2}}

3 (\frac{1}{2})^{x}

\frac{3 x ^{2} - 12 x}{x ^{2} - 2 x - 3}

What is the asymptotes of f(x)=(2x^2-8)/(x-1) ?
The asymptotes of f(x)=(2x^2-8)/(x-1) is Vertical: x=1,Slant: y=2x+2