What is the domain of f(x)=(sqrt(x+4))/(x-1) ?

The domain of f(x)=(sqrt(x+4))/(x-1) is -4 1

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domain of f(x)=(sqrt(x+4))/(x-1)

domain

f (x) = \frac{x + 4}{x - 1}

- 4 \leq x < 1 or x > 1

Interval Notation

[- 4, 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 4

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

- 4 \leq x < 1 or x > 1

x^{2} - 2 x

f (x) = - 2 \cdot (5)^{x + 3}

f (x) = \frac{x ^{2} + x - 6}{x ^{2} + 3 x - 4}

\frac{( 2 x + 15 )}{x - 3}

f (x) = - (x + 2)^{2} + 4

What is the domain of f(x)=(sqrt(x+4))/(x-1) ?
The domain of f(x)=(sqrt(x+4))/(x-1) is -4<= x<1\lor x>1