What is the range of f(x)=10^{x+3} ?

The range of f(x)=10^{x+3} is f(x)>0

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range of f(x)=10^{x+3}

range

f (x) = 1 0^{x + 3}

f (x) > 0

Interval Notation

(0, \infty)

Solution steps

The range of an exponential function of the form

c \cdot n^{a x + b} + k

f (x) > k

k = 0

f (x) > 0

f (x) = x^{2} - 2 x - 8

\frac{9 x ^{3}}{x - 6}

5 (x + 2)^{2} - 3

f (x) = - 3 cos (2 x + 3)

f (x) = x^{2} e^{- x}