What is the domain of (sqrt(x-2))^2+3 ?

The domain of (sqrt(x-2))^2+3 is x>= 2

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domain of (sqrt(x-2))^2+3

domain

(x - 2)^{2} + 3

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

- 2 cos (\frac{x}{3} - \frac{π}{9}) - 3

f (x) = \frac{1}{x ^{2} - 2 x}

f (x) = 4 - \frac{2}{t ^{2}}

f (x) = 3 x^{2} + 2 x - 3

f (x) = \frac{3 x}{2}