What is the domain of f(x)=ln(((x+1))/(x-1)) ?

The domain of f(x)=ln(((x+1))/(x-1)) is x 1

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domain of f(x)=ln(((x+1))/(x-1))

domain

f (x) = ln (\frac{( x + 1 )}{x - 1})

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

x < - 1 or x > 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 1

f (x) = 10 t e^{3 - t^{2}}

f (x) = 3 x + 4

f (x) = (x + 2)^{3} - 6

f (x) = \frac{x + 5}{x ^{3} - 12 x ^{2} + 20 x}

f (x) = \frac{x + 2}{x ^{2} + x - 6}

What is the domain of f(x)=ln(((x+1))/(x-1)) ?
The domain of f(x)=ln(((x+1))/(x-1)) is x<-1\lor x>1