What is the domain of f(x)= 8/((x-1)(x+2)) ?

The domain of f(x)= 8/((x-1)(x+2)) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 8/((x-1)(x+2))

domain

f (x) = \frac{8}{( x - 1 ) ( x + 2 )}

x < - 2 or - 2 < x < 1 or x > 1

Interval Notation

(- \infty, - 2) \cup (- 2, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 2

The function domain

x < - 2 or - 2 < x < 1 or x > 1

y = \frac{4 - x ^{2}}{x ^{2} - 1}

f (x) = \frac{2 x}{16 - x ^{2}}

f (x) = 4 e^{x}

f (x) = ∣ x + 2 ∣ - 1

What is the domain of f(x)= 8/((x-1)(x+2)) ?
The domain of f(x)= 8/((x-1)(x+2)) is x<-2\lor-2<x<1\lor x>1