What is the inverse of f(x)= 1/3 (x+2)^2-3 ?

The inverse of f(x)= 1/3 (x+2)^2-3 is sqrt(3x+9)-2,-sqrt(3x+9)-2

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inverse of f(x)= 1/3 (x+2)^2-3

inverse

f (x) = \frac{1}{3} (x + 2)^{2} - 3

3 x + 9 - 2, - 3 x + 9 - 2

Solution steps

y = \frac{1}{3} (x + 2)^{2} - 3

Replace

x

with

y

x = \frac{1}{3} (y + 2)^{2} - 3

Solve for

y, x = \frac{1}{3} (y + 2)^{2} - 3

3 x + 9 - 2, - 3 x + 9 - 2

f (x) = (8 - t)^{\frac{1}{4}}

\frac{3 x ^{3} - 6 x ^{2}}{x - 2}

f (x) = 2 4 - y

f (x) = x^{3} - 4 x + 8

f (x) = - \frac{1}{2} (x + 6)^{2} + 8

What is the inverse of f(x)= 1/3 (x+2)^2-3 ?
The inverse of f(x)= 1/3 (x+2)^2-3 is sqrt(3x+9)-2,-sqrt(3x+9)-2