What is the domain of (1/(sqrt(x)))/(x^2-4) ?

The domain of (1/(sqrt(x)))/(x^2-4) is 0 2

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domain of (1/(sqrt(x)))/(x^2-4)

domain

\frac{\frac{1}{x}}{x ^{2} - 4}

0 < x < 2 or x > 2

Interval Notation

(0, 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 2, x = - 2, x = 0

Combine real regions and undefined points for final function domain

0 < x < 2 or x > 2

f (x) = 2 - 5 x

y = - 5 + 4 x

f (x) = \frac{x}{x + 4}

f (x) = (x - 3)^{2} + 1

f (x) = \frac{x ^{2} + 5}{x ^{2} - 2 x - 15}

What is the domain of (1/(sqrt(x)))/(x^2-4) ?
The domain of (1/(sqrt(x)))/(x^2-4) is 0<x<2\lor x>2