What is the critical 6x^3-9x^2-36x ?

The critical 6x^3-9x^2-36x is x=-1,x=2

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critical 6x^3-9x^2-36x

critical points

6 x^{3} - 9 x^{2} - 36 x

x = - 1, x = 2

Solution steps

6 x^{3} - 9 x^{2} - 36 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 2

Identify critical points not in

f (x)

domain

Domain of

6 x^{3} - 9 x^{2} - 36 x : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 2

f (x) = \frac{1}{4} x - 9

f (x) = 16 - 4 x

3 x (x - 2)^{3}

f (x) = \frac{x}{x + 4}

\frac{( 5 x + 4 )}{( x ^{(2)} + 3 x + 2 )}