What is the extreme f(x)=x^3-27x+10 ?

The extreme f(x)=x^3-27x+10 is Maximum(-3,64),Minimum(3,-44)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-27x+10

extreme points

f (x) = x^{3} - 27 x + 10

Maximum (- 3, 64), Minimum (3, - 44)

Solution steps

f^{'} (x) = 3 x^{2} - 27

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

x^{3} - 27 x + 10 : 64

Maximum (- 3, 64)

Plug

x = 3

into

x^{3} - 27 x + 10 : - 44

Minimum (3, - 44)

Maximum (- 3, 64), Minimum (3, - 44)

(53) (5 - 8)

f (x) = - \frac{1}{5} x

(- 1.8) (- 9.6)

7 sin (4 (t + 7)) - 8

f (x) = \frac{( x ^{2} - 1 )}{2 x ^{2} - x - 3}

What is the extreme f(x)=x^3-27x+10 ?
The extreme f(x)=x^3-27x+10 is Maximum(-3,64),Minimum(3,-44)