What is the range of f(x)=sqrt(x)-1 ?

The range of f(x)=sqrt(x)-1 is f(x)>=-1

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range of f(x)=sqrt(x)-1

range

f (x) = x - 1

f (x) \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = - 1

f (x) \geq - 1

f (x) = \frac{1}{x + 7}

f (x) = (4 - 7 x)^{\frac{7}{2}}

3 x - 7 y = 14

f (x) = \frac{2 x - 6}{x + 4}

y = 9 x + 6