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Popular >

range of-(x+1)^2+4

Solution

range

- (x + 1)^{2} + 4

Solution

f (x) \leq 4

+1

Interval Notation

(- \infty, 4]

Solution steps

Vertex of

- (x + 1)^{2} + 4 :

Maximum

(- 1, 4)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (- 1, 4)

f (x) \leq 4

Popular Examples

range of f(x)=(x-1)^2-2 range

f (x) = (x - 1)^{2} - 2

inverse of f(x)=(x+3)/(2x-1)inverse

f (x) = \frac{x + 3}{2 x - 1}

inverse of sqrt(6x+24)inverse

6 x + 24

domain of ln(x^3+x^2-2x)domain

ln (x^{3} + x^{2} - 2 x)

inverse of f(x)=9+sqrt(4+x)inverse

f (x) = 9 + 4 + x

Frequently Asked Questions (FAQ)

What is the range of-(x+1)^2+4 ?
The range of-(x+1)^2+4 is f(x)<= 4