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Popular >

extreme f(x)=x^2+12x+11

Solution

extreme points

f (x) = x^{2} + 12 x + 11

Solution

Minimum (- 6, - 25)

Solution steps

f^{'} (x) = 2 x + 12

Find intervals:

Decreasing

: - \infty < x < - 6,

Increasing

: - 6 < x < \infty

Plug

x = - 6

into

x^{2} + 12 x + 11 : - 25

Minimum (- 6, - 25)

Popular Examples

parity f(x)=-8x^7-x^5+2x^3 parity

f (x) = - 8 x^{7} - x^{5} + 2 x^{3}

extreme f(x)= 1/(x(x-1)(x+1))extreme points

f (x) = \frac{1}{x ( x - 1 ) ( x + 1 )}

distance (-1,1),(-10,-5)distance

(- 1, 1), (- 10, - 5)

domain of \sqrt[3]{x}-4 domain

asymptotes of f(x)=(5x-2)/(2(5x-9))asymptotes

f (x) = \frac{5 x - 2}{2 ( 5 x - 9 )}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+12x+11 ?
The extreme f(x)=x^2+12x+11 is Minimum(-6,-25)