What is the domain of sqrt(x^2-2x-8) ?

The domain of sqrt(x^2-2x-8) is x = 4

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domain of sqrt(x^2-2x-8)

domain

x^{2} - 2 x - 8

x \leq - 2 or x \geq 4

Interval Notation

(- \infty, - 2] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 4

The function domain

x \leq - 2 or x \geq 4

(9, - 9), (- 4, 5)

f (x) = a^{x}

f (t) = cosh^{2} (t)

7 + 2 x

f (x) = x^{4} + x^{3} + x^{2} + 1

What is the domain of sqrt(x^2-2x-8) ?
The domain of sqrt(x^2-2x-8) is x<=-2\lor x>= 4