What is the critical f(x)=2x^2+4x-3 ?

The critical f(x)=2x^2+4x-3 is x=-1

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critical f(x)=2x^2+4x-3

critical points

f (x) = 2 x^{2} + 4 x - 3

x = - 1

Solution steps

2 x^{2} + 4 x - 3

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1

Identify critical points not in

f (x)

domain

Domain of

2 x^{2} + 4 x - 3 : - \infty < x < \infty

All critical points are in domain

x = - 1

f (x) = \frac{t + 2}{t ^{2} + 5 t + 6}

f (x) = \frac{2 x}{x ^{2} + 4}

15 x - 6 y = 16

f (x) = - x^{3} + 3 x^{2} - 7

f (x) = x^{2} - 4 x + 7