What is the domain of f(x)=(8x+3)/(7x+9) ?

The domain of f(x)=(8x+3)/(7x+9) is x -9/7

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domain of f(x)=(8x+3)/(7x+9)

domain

f (x) = \frac{8 x + 3}{7 x + 9}

x < - \frac{9}{7} or x > - \frac{9}{7}

Interval Notation

(- \infty, - \frac{9}{7}) \cup (- \frac{9}{7}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{9}{7}

The function domain

x < - \frac{9}{7} or x > - \frac{9}{7}

f (x) = \frac{( x - 10 ) ^{3}}{10} + 5

f (x) = \frac{1}{e ^{x} - 1}

g (t) = t 4 - t

f (x) = \frac{( x + \frac{1}{x} + 11 )}{x + \frac{1}{x} + 2}

f (x) = \frac{1}{4} x - \frac{1}{2}

What is the domain of f(x)=(8x+3)/(7x+9) ?
The domain of f(x)=(8x+3)/(7x+9) is x<-9/7 \lor x>-9/7