What is the domain of (5-x)/(x^2-4x) ?

The domain of (5-x)/(x^2-4x) is x 4

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domain of (5-x)/(x^2-4x)

domain

\frac{5 - x}{x ^{2} - 4 x}

x < 0 or 0 < x < 4 or x > 4

Interval Notation

(- \infty, 0) \cup (0, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = 0

The function domain

x < 0 or 0 < x < 4 or x > 4

\frac{2}{x}

3 x + y - 2 = 0

f (x) = \frac{1}{2} - \frac{1}{2} cos (2 x - \frac{π}{4})

f (x) = \frac{x}{x ^{2} - 3 x + 2}

f (x) = \frac{( 2 x + 4 )}{( x ^{2} - 16 )}

What is the domain of (5-x)/(x^2-4x) ?
The domain of (5-x)/(x^2-4x) is x<0\lor 0<x<4\lor x>4