What is the critical (x^2-2x-1)/(x+1) ?

The critical (x^2-2x-1)/(x+1) is x=-1-sqrt(2),x=-1+sqrt(2)

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critical (x^2-2x-1)/(x+1)

critical points

\frac{x ^{2} - 2 x - 1}{x + 1}

x = - 1 - 2, x = - 1 + 2

Solution steps

\frac{x ^{2} - 2 x - 1}{x + 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1 - 2, x = - 1 + 2, x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 2 x - 1}{x + 1} : x < - 1 or x > - 1

\frac{x ^{2} - 2 x - 1}{x + 1}

is not defined at

x = - 1

, therefore:

x = - 1 - 2, x = - 1 + 2

(- 1, 3), (8, - 5)

- 8 x^{2} + 4 x - 2

\frac{x ^{2} - 9 x + 39}{x - 7}

f (x) = \frac{1}{x + 6}

f (x) = 2 x^{2} - 4 x - 5

What is the critical (x^2-2x-1)/(x+1) ?
The critical (x^2-2x-1)/(x+1) is x=-1-sqrt(2),x=-1+sqrt(2)