What is the midpoint (-7/2 , 1/3),(1/2 , 10/3) ?

The midpoint (-7/2 , 1/3),(1/2 , 10/3) is (-3/2 , 11/6)

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midpoint (-7/2 , 1/3),(1/2 , 10/3)

midpoint

(- \frac{7}{2}, \frac{1}{3}), (\frac{1}{2}, \frac{10}{3})

(- \frac{3}{2}, \frac{11}{6})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- \frac{7}{2}, \frac{1}{3}), (x_{2}, y_{2}) = (\frac{1}{2}, \frac{10}{3})

= (\frac{\frac{1}{2} - \frac{7}{2}}{2}, \frac{\frac{10}{3} + \frac{1}{3}}{2})

Refine

= (- \frac{3}{2}, \frac{11}{6})

6 x + 2

f (x) = x^{2} \cdot ln (\frac{x}{2})

f (x) = 4 - \frac{3}{2} x

f (t) = (16 - t)^{\frac{1}{6}}

f (x) = lo g_{6} (x - 1)

What is the midpoint (-7/2 , 1/3),(1/2 , 10/3) ?
The midpoint (-7/2 , 1/3),(1/2 , 10/3) is (-3/2 , 11/6)