What is the domain of f(x)=sqrt(x^2+2x-15) ?

The domain of f(x)=sqrt(x^2+2x-15) is x = 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(x^2+2x-15)

domain

f (x) = x^{2} + 2 x - 15

x \leq - 5 or x \geq 3

Interval Notation

(- \infty, - 5] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 5 or x \geq 3

The function domain

x \leq - 5 or x \geq 3

f (x) = \frac{1 - x}{x}

(2, - 5), (4, 7)

(6.1) (- 2.5)

f (x) = \frac{( 2 x ^{2} - 3 x - 20 )}{x - 5}

\frac{3}{x - 2}

What is the domain of f(x)=sqrt(x^2+2x-15) ?
The domain of f(x)=sqrt(x^2+2x-15) is x<=-5\lor x>= 3