What is the domain of f(x)=(2x+1)/(2x^2+3x+1) ?

The domain of f(x)=(2x+1)/(2x^2+3x+1) is x -1/2

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domain of f(x)=(2x+1)/(2x^2+3x+1)

domain

f (x) = \frac{2 x + 1}{2 x ^{2} + 3 x + 1}

x < - 1 or - 1 < x < - \frac{1}{2} or x > - \frac{1}{2}

Interval Notation

(- \infty, - 1) \cup (- 1, - \frac{1}{2}) \cup (- \frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{1}{2}, x = - 1

The function domain

x < - 1 or - 1 < x < - \frac{1}{2} or x > - \frac{1}{2}

x^{2} + 2 x - 9

y = x^{3} + 3 x^{2} + 3 x + 2

2 cos (x) + sin (2 x)

f (x) = sin (4 sin (4 x))

What is the domain of f(x)=(2x+1)/(2x^2+3x+1) ?
The domain of f(x)=(2x+1)/(2x^2+3x+1) is x<-1\lor-1<x<-1/2 \lor x>-1/2