What is the domain of y=sqrt(x^2-4) ?

The domain of y=sqrt(x^2-4) is x = 2

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domain of y=sqrt(x^2-4)

domain

y = x^{2} - 4

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

sin (2 x)

\frac{8 ( \frac{6}{5 x - 4} ) + 4}{x - 4}

11

121

f (x) = \frac{x + 2}{4 - x}

What is the domain of y=sqrt(x^2-4) ?
The domain of y=sqrt(x^2-4) is x<=-2\lor x>= 2