What is the range of x^2-6,x<= 0 ?

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range of x^2-6,x<= 0

range

x^{2} - 6, x \leq 0

f (x) \geq - 6

Interval Notation

[- 6, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

x^{2} - 6, x \leq 0 : x \leq 0

Extreme Points of

x^{2} - 6, x \leq 0 :

Minimum

(0, - 6)

Find the range for the interval

- \infty < x \leq 0 : - 6 \leq f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) \geq - 6

f (x) = \frac{1}{3 x + 6}

y = 3 x + 2

2 x + y = - 7

\frac{( x ^{2} - 2 )}{( 4 x ^{5} + 2 x ^{3} - 3 x + 1 )}

ln (7 - x)