What is the domain of f(x)=sqrt((2x)/(x+1)) ?

The domain of f(x)=sqrt((2x)/(x+1)) is x = 0

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domain of f(x)=sqrt((2x)/(x+1))

domain

f (x) = \frac{2 x}{x + 1}

x < - 1 or x \geq 0

Interval Notation

(- \infty, - 1) \cup [0, \infty)

Solution steps

Find non-negative values for radicals:

x < - 1 or x \geq 0

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x \geq 0

f (x) = 15 + 5 x

\frac{2 x - 3}{x + 4}

f (x) = \frac{6 x + 7}{5 x + 9}

(- 2, - 8), (3, 2)

- cos (x - π) - 1

What is the domain of f(x)=sqrt((2x)/(x+1)) ?
The domain of f(x)=sqrt((2x)/(x+1)) is x<-1\lor x>= 0