What is the monotone f(x)=x^3-3x+8 ?

The monotone f(x)=x^3-3x+8 is Increasing:-infinity <x<-1,Decreasing:-1<x<1,Increasing:1<x<infinity

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monotone f(x)=x^3-3x+8

monotone intervals

f (x) = x^{3} - 3 x + 8

Increasing : - \infty < x < - 1, Decreasing : - 1 < x < 1, Increasing : 1 < x < \infty

Solution steps

f^{'} (x) = 3 x^{2} - 3

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Increasing : - \infty < x < - 1, Decreasing : - 1 < x < 1, Increasing : 1 < x < \infty

f (x) = \frac{( 28 x + 7 )}{x ^{2}}

x^{2} - 144

4 x - x^{2}

f (x) = \frac{x ^{2} + x - 6}{x - 2}

f (x) = 7 - 3 x^{3}

What is the monotone f(x)=x^3-3x+8 ?
The monotone f(x)=x^3-3x+8 is Increasing:-infinity <x<-1,Decreasing:-1<x<1,Increasing:1<x<infinity