What is the domain of f(x)= 5/(x^2+4x) ?

The domain of f(x)= 5/(x^2+4x) is x 0

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domain of f(x)= 5/(x^2+4x)

domain

f (x) = \frac{5}{x ^{2} + 4 x}

x < - 4 or - 4 < x < 0 or x > 0

Interval Notation

(- \infty, - 4) \cup (- 4, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 4

The function domain

x < - 4 or - 4 < x < 0 or x > 0

f (x) = \frac{7 x + 2 x}{x}

f (x) = \frac{x ^{2} + 2 x + 4}{x ^{2} + 2 x}

\frac{3 x + 4}{2 x - 1}

f (x) = \frac{x ^{2} - 2 x}{x ^{4} - 16}

ln (3 x)

What is the domain of f(x)= 5/(x^2+4x) ?
The domain of f(x)= 5/(x^2+4x) is x<-4\lor-4<x<0\lor x>0