What is the asymptotes of f(x)=(x^2-2x)/(x^4-16) ?

The asymptotes of f(x)=(x^2-2x)/(x^4-16) is Vertical: x=-2,Horizontal: y=0

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asymptotes of f(x)=(x^2-2x)/(x^4-16)

asymptotes

f (x) = \frac{x ^{2} - 2 x}{x ^{4} - 16}

Vertical : x = - 2, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 2 x}{x ^{4} - 16} : x = - 2

Horizontal Asymptotes of

\frac{x ^{2} - 2 x}{x ^{4} - 16} : y = 0

Slant Asymptotes of

\frac{x ^{2} - 2 x}{x ^{4} - 16} :

None

Vertical : x = - 2, Horizontal : y = 0

ln (3 x)

y = x^{3} = - 7 x^{2} - 24 x + 9

f (x) = x - 8

f (x) = 9 x - 10

What is the asymptotes of f(x)=(x^2-2x)/(x^4-16) ?
The asymptotes of f(x)=(x^2-2x)/(x^4-16) is Vertical: x=-2,Horizontal: y=0