What is the inverse of f(x)=9sqrt(x)-10 ?

The inverse of f(x)=9sqrt(x)-10 is (x^2)/(81)+(20x)/(81)+100/81

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inverse of f(x)=9sqrt(x)-10

inverse

f (x) = 9 x - 10

\frac{x ^{2}}{81} + \frac{20 x}{81} + \frac{100}{81}

Solution steps

y = 9 x - 10

Replace

x

with

y

x = 9 y - 10

Solve for

y, x = 9 y - 10

\frac{x ^{2}}{81} + \frac{20 x}{81} + \frac{100}{81}

f (x) = \frac{( x - 3 )}{x ^{2} - 4}

f (x) = 4 x^{2} - 12 x + 9

20 x csc (5 x^{2} + 2) d x

(- 4.8) (- 7)

f (x) = \frac{1}{2} (3)^{x + 4} - 5

What is the inverse of f(x)=9sqrt(x)-10 ?
The inverse of f(x)=9sqrt(x)-10 is (x^2)/(81)+(20x)/(81)+100/81