What is the domain of y=(x^2-9)/(2x^2+4) ?

The domain of y=(x^2-9)/(2x^2+4) is -infinity <x<infinity

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domain of y=(x^2-9)/(2x^2+4)

domain

y = \frac{x ^{2} - 9}{2 x ^{2} + 4}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

x = 0

(- \frac{4}{7}, \frac{4}{7}), (\frac{8}{5}, \frac{4}{5})

y = - \frac{3}{2} x - 7, (3, - 2)

f (x) = \frac{x + 4}{x - 3}

What is the domain of y=(x^2-9)/(2x^2+4) ?
The domain of y=(x^2-9)/(2x^2+4) is -infinity <x<infinity