What is the line (-4/7 , 4/7),(8/5 , 4/5) ?

The line (-4/7 , 4/7),(8/5 , 4/5) is y= 2/19 x+12/19

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line (-4/7 , 4/7),(8/5 , 4/5)

line

(- \frac{4}{7}, \frac{4}{7}), (\frac{8}{5}, \frac{4}{5})

y = \frac{2}{19} x + \frac{12}{19}

Solution steps

Find the line

y = mx + b

passing through

(- \frac{4}{7}, \frac{4}{7})

(\frac{8}{5}, \frac{4}{5})

Compute the slope

(- \frac{4}{7}, \frac{4}{7}), (\frac{8}{5}, \frac{4}{5}) : m = \frac{2}{19}

Compute the

y

intercept:

b = \frac{12}{19}

Construct the line equation

y = mx + b

where

m = \frac{2}{19}

and

b = \frac{12}{19}

y = \frac{2}{19} x + \frac{12}{19}

y = - \frac{3}{2} x - 7, (3, - 2)

f (x) = \frac{x + 4}{x - 3}

f (x) = (x + 2)^{3} + 1

f (x) = (\frac{1}{3})^{x}

y = \frac{5 x}{x ^{2} - 2 x}

What is the line (-4/7 , 4/7),(8/5 , 4/5) ?
The line (-4/7 , 4/7),(8/5 , 4/5) is y= 2/19 x+12/19