What is the perpendicular y=-3/2 x-7,(3,-2) ?

The perpendicular y=-3/2 x-7,(3,-2) is y= 2/3 x-4

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perpendicular y=-3/2 x-7,(3,-2)

perpendicular

y = - \frac{3}{2} x - 7, (3, - 2)

y = \frac{2}{3} x - 4

Solution steps

Find the line

y = mx + b

perpendicular to

y = - \frac{3}{2} x - 7

that passes through

(3, - 2)

Find the slope of

y = - \frac{3}{2} x - 7 : m = - \frac{3}{2}

Compute the slope of the perpendicular line:

m_{p} = \frac{2}{3}

Find the line with slope m=

\frac{2}{3}

and passing through

(3, - 2) : y = \frac{2}{3} x - 4

y = \frac{2}{3} x - 4

f (x) = \frac{x + 4}{x - 3}

f (x) = (x + 2)^{3} + 1

f (x) = (\frac{1}{3})^{x}

y = \frac{5 x}{x ^{2} - 2 x}

x - 7 x^{\frac{1}{7}}

What is the perpendicular y=-3/2 x-7,(3,-2) ?
The perpendicular y=-3/2 x-7,(3,-2) is y= 2/3 x-4